On Wednesday, 29 January 2014 at 10:55:57 UTC, Cooler wrote:
Consider 3 functions taking array as an argument:
void fun1(in int[] x){...}
void fun2(ref int[] x){...}
void fun3( int[] x){...}
auto a = new int[10];
fun1(a); // Guaranteed that "a" will not be changed
fun2(a); // Guaranteed that we will see any change to "a", made
in fun2()
fun3(a); // Changes to "a" in fun3() may be or may be not
visible to the caller
In case of fun3() we have ambiguous behaviour, depending on the
body of the function.
Am I right?
Is that intentional?
Arrays are a pair of pointer and length.
fun1 marks the pointer, the length and the data pointed as const.
fun3 marks nothing const, but since pointer and length are passed
by value, you'll only see changes to the content of x.
fun2 is like fun3, but pointer and length are itself passed by
reference.
