On Wednesday, 12 March 2014 at 02:14:45 UTC, bearophile wrote:
ed:
I am trying to convert a 1D array to a 2D array
If you have a dynamic array (1D), you can convert it to a
dynamic array of dynamic arrays (2D) using chunks:
void main() {
import std.stdio, std.range, std.algorithm;
int[] a = [1, 2, 3, 4, 5, 6];
int[][] b = a.chunks(2).array;
b.writeln;
}
Output:
[[1, 2], [3, 4], [5, 6]]
Your problems are caused by mixing fixed-size arrays (that are
values, allocated in-place), with dynamic arrays (that are
little length+pointer structs that often point to
heap-allocated memory).
Bye,
bearophile
Thanks for explaining this, it makes sense what you said. But I'm
still not sure why my original Example 1 worked.
~~~
// This works OK and converts long[4] to int[] then implicitly to
int[2][2]
long[4] a=[1,2,3,4];
int[2][2] b = to!(int[])(a);
// Why does this not work the same way?
long[4] a=[1,2,3,4];
int[2][2] b;
b = to!(int[])(a);
~~~
My understanding of your explanation is that it shouldn't work.
Cheers,
ed
