On Friday, 21 March 2014 at 13:59:27 UTC, Vladimir Panteleev
wrote:
On Friday, 21 March 2014 at 12:32:58 UTC, Sergei Nosov wrote:
On Thursday, 20 March 2014 at 21:25:03 UTC, Ali Çehreli wrote:
This is a somewhat common little exercise: Write a function
that takes the size of a diamond and produces a diamond of
that size.
When printed, here is the output for size 11:
*
***
*****
*******
*********
***********
*********
*******
*****
***
*
What interesting, boring, efficient, slow, etc. ways are
there?
Ali
Probably, the most boring way is
foreach(i; 0..N)
{
foreach(j; 0..N)
write(" *"[i + j >= N/2 && i + j < 3*N/2 && i - j <=
N/2 && j - i <= N/2]);
write(" *"[abs(i-N/2) + abs(j-N/2) <= N/2]);
writeln;
}
Beat me. Yours is even more boring. =)
