On Monday, 2 June 2014 at 20:23:12 UTC, Steven Schveighoffer
wrote:
On Mon, 02 Jun 2014 15:58:01 -0400, Steven Schveighoffer
<schvei...@yahoo.com> wrote:
I'm trying to think of a way to do this without loops, but not
sure.
I'm surprised, I looked for some kind of "apply" function like
map, but just calls some function with each element in the
range.
Something like this would make this a 1 (2?) liner:
if(i == t.length) writeln(t) else each!((x) => {t[i] = x;
foo(i+1);})(iota(x.length));
But I can't find a phobos primitive for each. Would have
expected it in std.algorithm or std.functional?
-Steve
Its been discussed a few times. There were some objections (IIRC
Walter thought that there was no significant advantage over plain
foreach).
