Re: alias with lambda syntax: alias fun2=a=>fun(a);

[timotheecour via Digitalmars-d-learn]

On Thursday, 5 June 2014 at 06:58:50 UTC, Timothee Cour via
Digitalmars-d-learn wrote:

Is there a way to do this?

import std.algorithm;

auto fun(T)(T a){return a;}

template fun2(T){auto fun2(T a){return fun(a);}}//OK but heavy syntax and

cannot be nested inside test()

void main(){

//alias fun2=fun!int; //OK but needs to specify template params

  //none of those work:
  //alias fun2=a=>fun(a);
  //alias fun2(T)=(T a)=>fun(a);
  //alias fun2(T)=(T a){return fun(a);}
  auto b=[1].map!fun2;
  assert(b.equal([1]));
}

ok I remembered we can use std.typetuple.Alias for that.