Thanks Marc. Not sure what to do here. I need to the binary data
to be exactly the number of bytes as specified by the struct.
How to handle the conversion from string to char[]?
TJB
(You forgot to include the error. For other readers: It fails
to compile with "template std.conv.toImpl cannot deduce
function from argument types !(char[4])(string)" and similar
error messages.)
This is caused by the two `char` arrays. `std.conv.to` cannot
convert strings to fixed-size char arrays, probably because
it's not clear what should happen if the input string is too
long or too short.
Would it be a good idea to support this?
As a workaround, you could declare a second struct with the
same members, but `ex` and `mmid` as strings, read your data
into these, and assign it to the first structure:
import std.algorithm;
import std.csv;
import stdio = std.stdio;
import std.stream;
align(1) struct QuotesBinDummy
{
int qtim;
int bid;
int ofr;
int bidsiz;
int ofrsiz;
short mode;
string ex;
string mmid;
}
align(1) struct QuotesBin
{
int qtim;
int bid;
int ofr;
int bidsiz;
int ofrsiz;
short mode;
char[1] ex;
char[4] mmid;
}
void main()
{
string infile = "temp.csv";
string outfile = "temp.bin";
Stream fin = new BufferedFile(infile);
Stream fout = new BufferedFile(outfile, FileMode.Out);
foreach(ulong n, char[] line; fin)
{
auto temp = csvReader!QuotesBinDummy(line).front;
QuotesBin record;
record.tupleof = temp.tupleof;
fout.writeExact(&record, QuotesBin.sizeof);
}
fin.close();
fout.close();
}
The line "record.tupleof = temp.tupleof;" will however fail
with your example data, because the `ex` field includes a space
in the CSV, and the last field is empty, but needs to be 4
chars long.
