Re: Iterating over the tupleof of a struct

[Ali Çehreli via Digitalmars-d-learn]

On 08/23/2014 10:21 AM, Meta wrote:
On Saturday, 23 August 2014 at 01:56:06 UTC, Dicebot wrote:
On Saturday, 23 August 2014 at 01:32:13 UTC, Meta wrote:
On Saturday, 23 August 2014 at 01:24:10 UTC, Meta wrote:
What is happening here? Are these two extra ulongs the offsets of
the fields in the struct?

And I just realized that that's obviously not the case. It's just an
iteration variable. Problem solved.

It is same with arrays:

int[] arr = [ 1, 2, 3 ];

// ok, iterates elements
foreach (elem; arr) { }

// also ok, iterates elements + counts current index
foreach (index, elem; arr) { }

Yeah, I got confused as I expected

     foreach (val1, val2; test.tupleof)
     {
         //...
     }

To destructure the result of test.tupleof, but I just got an iteration
variable instead.

There are a number of inconsistencies around tuples. The behavior you 
expect is present for ranges that return tuple fronts:

import std.stdio;
import std.typecons;
import std.range;

void main()
{
    auto t = [ tuple(1.5, 100), tuple(2.5, 200) ];

    foreach (a, b; t.retro) {
        writefln("%s, %s", a, b);
    }
}

Because t.retro is a range, the foreach extracts the members of the 
tuple and we get the folloing output:

2.5, 200
1.5, 100

Now, remove the .retro part; the range becomes a slice, in which case 
'a' becomes the iteration counter and 'b' becomes the tuple value:

0, Tuple!(double, int)(1.5, 100)
1, Tuple!(double, int)(2.5, 200)

Is that a WAT? :)

Ali