On Wednesday, 3 September 2014 at 20:46:40 UTC, monarch_dodra
wrote:
On Wednesday, 3 September 2014 at 19:43:26 UTC, Nordlöw wrote:
Is there a simpler way to way to
s ~= repeat('*', n).array.to!string;
if s has to be of type string?
s ~= repeat('*', n).array();
Should be enough. Why the "to!string"?
There's 1 useless allocation, but I think that's OK for code
this trivial?
Else, you can do:
s.length+=n;
s[$-n .. $] []= '*';
This is also relatively simple. The ownside is doing double
assignement, as "length" will initialize new elements to
"char.init". Probably not noticeable.
There *might* be more "efficient" ways to do it, but I'd doubt
it qualifies as "simpler". Or if it's really observeable. Are
these good enough for you?
hello Nordlöw a time I did something like that, see.
string repet(string a, int i)
{
int b;
string c;
for(b=0;b<=i;b++)
{c ~= a;}
return c;
}
can be adapted to char[].
