On Tue, 16 Sep 2014 14:37:05 +0000, Jay wrote:

> all the functions/methods i've come across so far deal with either
> streams or just file names (like std.file.read) and there doesn't seem
> to be a way to wrap a std.stdio.File in a stream (or is there?). i need
> a function that takes a std.stdio.File and returns a string or byte
> array.

The short answer is no.  I usually use something like this:

    // Lazy
    auto stream = stdin.byChunk(4096).joiner();

You can make it eager by tacking a `.array` on the end.  Functions used 
are from std.stdio, std.algorithm, std.array.

Reply via email to