Re: input range from stdin

[Ali Çehreli via Digitalmars-d-learn]

On 09/17/2014 08:30 AM, krzaq wrote:
On Wednesday, 17 September 2014 at 14:37:21 UTC, Marc Schütz wrote:
On Wednesday, 17 September 2014 at 12:44:00 UTC, krzaq wrote:
I'd like to have something similar to C++'s
std::istream_iterator<int>(std::cin)
Is it possible? I'm relatively indifferent to efficiency of the
solution.

import std.stdio;
import std.algorithm;
import std.conv;
writeln(stdin.byLine.map!(to!int));

What happens if I later have some strings that I want to read from the
same line?

How can I use the resultant range with std.fill?

My idea doesn't seem to work: http://dpaste.dzfl.pl/130e14c927f3

The following worked:

import std.stdio;
import std.format;
import std.exception;
import std.string;
import std.algorithm;

struct Data
{
    int i;
    string s;
}

Data toData(char[] line)
{
    int i;
    string s;
    auto slice = line;

    const items = formattedRead(line, " %s %s", &i, &s);
    enforce (items == 2, format("Incomplete line: %s", slice));

    return Data(i, s);
}

void main()
{
    auto data = stdin.byLine.map!toData;
    writeln(data);
}

I could not get it work with fill because fill requires specific types 
of ranges, which neither the destination nor the source were. For 
example, I wanted to use std.array.Appender but fill wants an 
InputRange. Also, the source is not a ForwardRange because it is 
consuming from stdin.

However, it is easy to make an array with std.array.array:

    import std.array;
    writeln(data.array);

Ali