Re: Why is amap implemented as a member function of TaskPool?

[Jared via Digitalmars-d-learn]

On Thursday, 18 September 2014 at 19:49:00 UTC, Atila Neves wrote:

Or what I really want to ask: why can't I call amap from std.parallelism with a lambda? I assume it's because it's a member function but I'm not 100% sure.

Atila

You have to tell DMD that the lambda is not in fact a delegate.

import std.stdio;
import std.range;
import std.parallelism;

void main()
{
    auto w = iota(0,1_000_000);
    int[] foo;

    // Not OK, dmd can't infer lambda isn't a delegate
    // foo = taskPool().amap!(a => a + 1)(w);

    // OK:
    foo = taskPool().amap!`a+1`(w); // string lambdas, yeah!
    foo = taskPool().amap!(function int(int a) => a + 1)(w);
    static int func(int a) { return a + 1; }
    foo = taskPool().amap!func(w);
}