On Wednesday, 22 October 2014 at 01:02:17 UTC, bearophile wrote:
neal:
Anybody have any suggestions?
Something like this, perhaps?
data.sort!q{ a[4] > b[4] };
Bye,
bearophile
Hmmm.. Im getting some interesting results here. So when i put
all of the populations in an area and used this code:
sort!("a>b")(population);
writeln("Top 5 population in 1993: ");
for(int i = 0; i < 5;i++)
writeln(population[i]);
I get:
Top 5 population in 1993:
1189550675
916529257
264493898
191658591
156810428
The problem there is that i lose the country that the population
is associated with (the top one being China).
When I run your code:
data.sort!q{ a[4] > b[4] };
for(int i = 0; i < 5; i++)
writeln(data[][]);
I get this result for the top 5:
["Portugal", "1593140", "-668536", "1993", "9993683", "8"]
["Anguilla", "114", "-536", "1993", "9865", "10"]
["Malawi", "31745", "-25289", "1993", "9862531", "6"]
["Grenada", "2274", "-4890", "1993", "96908", "2"]
["Burkina Faso", "22613", "-38738", "1993", "9688261", "6"]
Notice that the top populations arent correct.
