// Assume bar is some associative array of type Foo[string]
Foo* value = key in bar;
if (!value) {
bar[key] = Foo.init;
value = &bar[key];
}
This seems sub-optimal, given that in involves three hashes (two lookups
and one insertion). Is there a more efficient or cleaner way to do so?
So basically:
Foo v = bar.get(key, Foo.init)
bar[key] = v;
Get is like an ordinary index but it will return the given value if it does not
exist in the AA.
Of course you probably want to create a new UFCS function to wrap your check +
default initialize if it doesn't exist.
T grab(T, U)(T[U] aa, U key) if (is(T == struct)) {
if (key !in aa)
aa[key] = new T;
return aa[key];
}
You are searching for the key twice and the original example used pointers.
There is a function called _aaGetX in the runtime that has exactly the required
behaviour:
// Get pointer to value in associative array indexed by key.
// Add entry for key if it is not already there.
void* _aaGetX(AA* aa, const TypeInfo keyti, in size_t valuesize, in void*
pkey)
however, using it in normal code could be considered a hack, because it belongs
to the internal implementation of associative arrays. Anyway, while waiting for
a better solution to present itself, we might as well have a look at this very
dirty one. ;)
extern(C) void* _aaGetX(void* aa, const TypeInfo keyti, in size_t
valuesize, in void* pkey);
V* aaGet(K, V)(V[K] arr, K key) {
return cast(V*)_aaGetX(cast(void*)&arr, typeid(K), V.sizeof,
cast(void*)&key);
}
unittest {
int[int] arr = [1: 10, 2: 20, 3: 30];
int *val = arr.aaGet(3); // an existing value
assert(*val == 30);
val = arr.aaGet(4); // aa[4] will be created
assert(*val == int.init);
assert(arr[4] == int.init);
}