On Friday, 24 April 2015 at 18:55:07 UTC, Steven Schveighoffer wrote:
On 4/24/15 2:50 PM, nrgyzer wrote:
On Friday, 24 April 2015 at 18:45:55 UTC, Jesse Phillips wrote:
On Friday, 24 April 2015 at 18:14:07 UTC, nrgyzer wrote:
Hi,

I'm looking for a function that converts my hex-string to a binary
representation. In Python I write the following:

myHex = "123456789ABCDEF"
myBin = myHex.decode('hex')

But how to do the same in D? Is there any function?

Thanks for suggestions!

   import std.stdio;
   void main(){
       import std.conv;
       import std.format;

       auto i = to!ulong("123456789ABCDEF", 16);

       writeln(format("%b", i));
   }

Thanks to all of you for the solutions, but what if the hex-string
exceeds the limit of ulong, for instance
"123456789ABCDEF0123456789ABCDEF1234". How to convert them to a
ulong-array?

Well, technically, a hex string can be split on 16-character boundaries, and then you could parse each one.

-Steve

Or use BigInt:

http://dlang.org/phobos/std_bigint.html

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