Re: Shortest way to allocate an array and initialize it with a specific value.

[via Digitalmars-d-learn]

On Thursday, 11 June 2015 at 08:33:46 UTC, Daniel Kozák wrote:

On Wed, 10 Jun 2015 20:22:17 +0000

Adel Mamin via Digitalmars-d-learn <digitalmars-d-learn@puremagic.com>

wrote:

ubyte[5] a = 0xAA; // Fine. Five 0xAA bytes.
auto a2 = new ubyte[5]; // Fine. Five 0 bytes.

Now, let's say, I want to allocate an array of a size, derived at run time, and initialize it to some non-zero value at the same time. What would be the shortest way of doing it?

import std.stdio;

struct Ubyte(ubyte defval) {
    ubyte v = defval;
    alias v this;
}

void main() {
        auto a2 = new Ubyte!(0xAA)[5];
        writeln(a2);
}

I like this one :-)