On Tuesday, 4 August 2015 at 10:29:57 UTC, 岩倉 澪 wrote:
On Tuesday, 4 August 2015 at 08:35:10 UTC, Dicebot wrote:
    auto output = receiveOnly!(immutable(Bar)[]);

Won't message passing like this result in an expensive copy, or does the cast to immutable via assumeUnique avoid that?

immutable data is implicitly shared and doesn't need to be duplicated - as it won't ever be modified, it is perfectly fine to do concurrent reads for that from multiple references.

std.concurrency does by-value message passing (in this case just ptr+length), it never deep copies automatically

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