Re: Use members of a Named Enum without using Enum name?

[Ali Çehreli via Digitalmars-d-learn]

On 08/15/2015 09:22 AM, QuizzicalFella wrote:
On Saturday, 15 August 2015 at 15:53:23 UTC, Adam D. Ruppe wrote:
On Saturday, 15 August 2015 at 15:37:42 UTC, QuizzicalFella wrote:
I'd like to be able to call someFunc(TRIANGLE) rather than
someFunc(PolygonT.TRIANGLE).

Two options come to mind:

alias TRIANGLE = PolygonT.TRIANGLE;
// etc

...if I wanted to write a mixin that iterated over all the elements in
an enum, how would I get a member to print its name without the type?
And how do I get the type to print itself?

foreach(member; enum)
     char[] output ~= "alias
"~member.name~"="~enum.name~"."~member.name~";"



Fundamentally, __traits(allMembers) and .stringof but the following 
enumMembers present them as a range:

import std.stdio;

enum PolygonT : byte { TRIANGLE, RECTANGLE, STAR }

auto enumMembers(E)()
{
    import std.conv : to;
    import std.algorithm : map;

    return [ __traits(allMembers, E) ].map!(a => a.to!string);
}

void info(E)()
{
    writefln("The members of %s: %-(%s, %)",
             E.stringof, enumMembers!PolygonT);
}

void main()
{
    info!PolygonT();
}

Ali