On Monday, 14 September 2015 at 15:04:00 UTC, Laeeth Isharc wrote:
On Monday, 14 September 2015 at 14:21:12 UTC, John Colvin wrote:
On Monday, 14 September 2015 at 14:05:01 UTC, Laeeth Isharc
wrote:
On Sunday, 13 September 2015 at 17:34:11 UTC, BBasile wrote:
On Sunday, 13 September 2015 at 17:24:20 UTC, Laeeth Isharc
wrote:
[...]
can't you use 'hasMember' (either with __traits() or
std.traits.hasMember)? It's more idiomatic than checking if
it's compilable.
I'll check again in a bit, but I seem to recall hasMember
didn't work. I would like to get the type of a member of a
type, and I think hasMember!(T.bar.date","hour") didn't work
for that. Possibly it does work and I messed it up somehow,
or it doesn't work and there is a more elegant way.
You mean hasMember!(typeof(T.bar.date), "hour"), right?
Ahh. Probably that was why (I will check it shortly). Why do
I need to do a typeof? What kind of thing is T.bar.date before
the typeof given that T is a type?
T.bar.date is just a symbol. If you tried to actually access it
then it would have to be a compile-time construct or be a static
member/method, but it's perfectly OK to ask what type it has or
what size it has.
The simple story: hasMember takes a type as its first argument.
T.bar.date isn't a type, it's a member of a member of a type. To
find out what type it is, use typeof.
