I have a situation where I would like to demonstrate violating
the contract of immutable (as an example of what not to do), but
do so without using structs or classes, just basic types and
pointers. The following snippet works as I would expect:
```
immutable int i = 10;
immutable(int*) pi = &i;
int** ppi = cast(int**)π
writeln(*ppi);
int j = 9;
*ppi = &j;
writeln(*ppi);
```
Two different addresses are printed, so I've successfully
violated the contract of immutable and changed the value of pi,
an immutable pointer. However, this does not work as I expect.
```
immutable int x = 10;
int* px = cast(int*)&x;
*px = 9;
writeln(x);
```
It prints 10, where I expected 9. This is on Windows. I'm curious
if anyone knows why it happens.
