On Wednesday, 18 November 2015 at 12:20:42 UTC, maik klein wrote:
https://stackoverflow.com/questions/33779822/unable-to-call-each-on-a-lockstep-range-containing-2-or-more-ranges
http://dpaste.dzfl.pl/76c79f1f12ab
void main(){
import std.container;
import std.stdio;
import std.algorithm.iteration;
import std.range;
Array!int ai = [1,2,3,4];
Array!int ai1 = [1,2,3,4];
Array!int ai2 = [1,2,3,4];
auto arange = lockstep(ai[],ai1[]);
arange.each!((a,b) => writeln(a, b));
auto arange2 = lockstep(ai[],ai1[],ai2[]);
arange2.each!((a,b,c) => writeln(a, b, c));
}
Error: template std.algorithm.iteration.each cannot deduce
function from argument types !((a, b, c) => writeln(a, b,
c))(Lockstep!(RangeT!(Array!int), RangeT!(Array!int),
RangeT!(Array!int))), candidates are:
/opt/compilers/dmd2/include/std/algorithm/iteration.d(820):
std.algorithm.iteration.each(alias pred = "a")
"arange" works but "arange2" doesn't because the compiler is
unable to deduce the the function. The error even appears if I
explicitly add the argument types.
Which version of the compiler are you using?
