On Monday, 30 November 2015 at 12:03:08 UTC, anonymous wrote:
On 30.11.2015 11:50, visitor wrote:though i don"t understand why it fails silently ??ref2491's original code is valid, but doesn't have the intended meaning. `e => {foo(e);}` is the same as `(e) {return () {foo(e);};}`, i.e. a (unary) function that returns a (nullary) delegate. Calling it does not run foo. In contrast, calling this runs foo: `e => foo(e)`.
Got it. Thank you)
