Hello. I want to define a template specialization using traits: import std.stdio, std.traits; void func(T)(T t) { writeln(1); } void func(T)(T t) if(isIntegral!T) { writeln(2); } void main() { func(1); }
But I'm getting an error saying that the called function matches both. If it were a single type, I know I have to put the specialization as in: void func(T: int)(T t) { writeln(2); } and that works, but how to make it more generic than that? -- Shriramana Sharma, Penguin #395953