On Sat, 16 Jan 2016 14:34:54 +0000, Samson Smith wrote: > I'm trying to make a fast little function that'll give me a random > looking (but deterministic) value from an x,y position on a grid. I'm > just going to run each co-ord that I need through an FNV-1a hash > function as an array of bytes since that seems like a fast and easy way > to go. I'm going to need to do this a lot and quickly for a real time > application so I don't want to waste a lot of cycles converting data or > allocating space for an array. > > In a nutshell how do I cast an int into a byte array? > > I tried this: > > byte[] bytes = cast(byte[])x; >> Error: cannot cast expression x of type int to byte[] > > What should I be doing instead?
You can do this: ubyte[] b = (cast(ubyte*) &a)[0 .. int.sizeof]; It is casting the pointer to `a` to a ubyte (or byte) pointer and then taking a slice the size of int.
