On 01/18/2016 11:12 PM, Albert00 wrote:
> On Tuesday, 19 January 2016 at 05:32:07 UTC, Ali Çehreli wrote:
>
> Ali, look what you said:
>
>> For example, the following is a row with two columns:
>>
>> int[2]
>
> Then you said:
>
>> So, in order to get 1 row of 2 columns, you would write
>>
>> int[2][1]
To rephrase myself, that is an array of 1 element, where the element
type is int[2]. So the only valid index is 0, which gives you an element
of int[2]. (You can further index into that element of course.)
> So the first pair of square-brackets is the column and second is the row
> as you said above,
I stress the fact that it is always the following syntax:
Type[length]
So, again, if we have an array of 1-element where the elements are of
type int[2], then it is this (space added for readability):
int[2] [1]
> but look what happens when I try to access thinking
> that way:
I suspect C and C++ way for inside-out (or is it outside-in) syntax is
affecting your thinking. ;)
> void main(){
> int[2][1] arr; // 2 columns & 1 row as Ali said...
>
> arr[0]
That one gives you the first element.
> [0] = 1;
and that one gives you the first element of that first element.
> arr[1][0] = 2;
Sorry, there is no element-1 for the arr: That has only one element.
> }
>
> ERROR:
>
> /d609/f167.d(14): Error: array index 1 is out of bounds arr[0 .. 1]
> /d609/f167.d(14): Error: array index 1 is out of bounds arr[0 .. 1]
>
>
> So now the first pair of brackets in fact is the ROW and the second is
> the COLUMN, because this works:
>
> void main(){
> int[2][1] arr; // 2 columns & 1 row
Yes, that's exactly what I said. :)
> arr[0][0] = 1;
> arr[0][1] = 2;
> }
>
> Maybe I'm really dumb,
Not at all. I blame C and C++. ;)
> but you need to agree that even with your good explanation it
> still doesn't making sense.
I don't agree: It makes sense and is consistent. :)
> Albert.
Ali
