On Friday, 19 February 2016 at 20:45:23 UTC, jmh530 wrote:
On Friday, 19 February 2016 at 15:00:51 UTC, jmh530 wrote:
This works.
But when I re-write foo to take that into account as in below,
I get an error that I can't implicitly convert int
function(int x) to int function(int x, int y).
I don't think I had looked at what you had done carefully
enough. Basically, you just define a new function and take a
function pointer of that. That might be a brute force solution.
I tried to use a cast (below) to modify the function pointer,
but it is printing the second number instead of the first. I
find this behavior strange...
int foo(int x)
{
return x;
}
void main()
{
import std.stdio : writeln;
auto foo_ = cast(int function(int x, int y)) &foo;
writeln(foo_(1, 200)); //prints 200
}
I don't think it's safe to convert between function pointer with
different number of arguments... It's possible to mess up the
stack frame.
Also '(int x, int y)=>f(x)' is clearly a delegate because it
refers to local variable 'f', you can't just cast it to 'int
function(int, int)'.
