On Wednesday, 17 August 2016 at 12:39:18 UTC, ag0aep6g wrote:
On 08/17/2016 02:08 PM, Eugene Wissner wrote:
I have a problem, that .stringof doesn't return what I'm
expecting.
Consider the following:
template A(string T)
{
enum A : bool
{
yes = true,
}
}
void main()
{
A!"asdf" a1;
typeof(a1) a2;
mixin(typeof(a1).stringof ~ " a3;");
}
I get an error: some.d-mixin-13|13 error| Error: template
some.A(string
T) is used as a type
Why the second line in main() works but the third one not?
typeof(a1).stringof seems to ignore the string template
parameter T.
pragma(msg, typeof(a1).stringof) would return just "A".
Is it a bug?
Not exactly a bug. .stringof gives you a simple, readable name.
It's not meant to be used in code generation. You can use
std.traits.fullyQualifiedName instead:
import std.traits: fullyQualifiedName;
mixin(fullyQualifiedName!(typeof(a1)) ~ " a3;");
What I find strange is that if A isn't a enum, but a class the
.stringof returns the full type name, therefore I would expect it
behave the same in the code above.
I will test later fullyQualifiedName, the example above is very
simplified version of the code I had problem with. Thanks anyway
