On Friday, 2 September 2016 at 06:56:07 UTC, Lutger wrote:
You could do: names.find("bob").chain(only(``)).front; It's not very expressive though.
Cauterite via Digitalmars-d-learn Fri, 02 Sep 2016 01:46:31 -0700
On Friday, 2 September 2016 at 06:56:07 UTC, Lutger wrote:
You could do: names.find("bob").chain(only(``)).front; It's not very expressive though.