On Thursday, 9 March 2017 at 16:14:28 UTC, Suliman wrote:
But now output is: [["```\r\nvoid foo()\r\n{\r\n\twriteln(\"ppp\");\r\n}\r\n```"]]But I do not \r\n\ symbols...
That's just the writeln array formatter. The matchFirst function returns an array of hits (that allows captures, btw you might need to use \( instead of ( to get the capture, god i hate regex) so writeln tries to print the whole array and that's how it does embedded newlines.
So you have the correct result, just written strangely.
