After trying and reading the specification, looks like nuts, but just wanted to confirm. Thx
can I overload operators as extension methods?
XavierAP via Digitalmars-d-learn Thu, 09 Mar 2017 15:56:56 -0800
The same way as T.foo() is lowered to foo(T) if no such member is
defined inside the type. It would allow me to extend 3rd party
types with operator notation without wrapping them.
- can I overload operators as extensio... XavierAP via Digitalmars-d-learn
- Re: can I overload operators as... Adam D. Ruppe via Digitalmars-d-learn
