On Saturday, 17 June 2017 at 13:03:28 UTC, ANtlord wrote:
Is GC called every iteration of this loop?
No, it will once on scope entry; where the deepest-referenced variable that is actually captured is defined. The compiler allocates heap space instead of stack space for the locals, then runs the function normally using that space.
The current implementation doesn't quite do this - it actually will alloc only once, on function entry, even when there's a variable inside a loop that is supposed to be independent. This is the cause of the commonly-referenced bug with foreach(i; whatever) capture(i); all showing the same number.
When that bug is fixed, it is possible to allocate on each loop... but your code doesn't anyway, so you're ok.
It will only alloc once. You can prove this with a debugger btw, set a breakpoint on `_d_allocmemory`.
