Re: spawnProcess: Exit parent process without terminating child process

[FreeSlave via Digitalmars-d-learn]

On Friday, 25 August 2017 at 19:55:09 UTC, timvol wrote:
Hi guys,
I want execute a process. I know, I can execute a process using 
"spawnProcess" or "executeShell". But I want exit the parent.

My code for testing purposes is the following:

int main(string[] asArgs_p)
{
    if ( (asArgs_p.length >= 2) && asArgs_p[1].isDir() )
    {
        while(1) {}
    }
    else
    {
        import std.process;
        spawnProcess([asArgs_p[0], "test"]);
    }
    return 0;
}

So, starting the application without any parameter, it calls 
"spawnProcess" with an parameter. Now, I want that the parent 
process (the process started without parameter) terminates, 
while the created process remains running.

At the moment, the parent process creates the child and remains 
open (because of the while(1)-loop).

Any ideas how I can exit the parent and keep the child process 
running?

Note that in your particular case the spawnProcess as used now 
should work too. It should run in parallel with its parent. 
Parent will exit and child process will remain. I'm not sure why 
the parent does not exit in your case. When starting this program 
without parameters it will not run into while(1) branch at all.