On Friday, 1 September 2017 at 09:38:59 UTC, Alex wrote:
Hi all!
Say, I have
struct A(T...)
{
T arr;
}
struct B(T...)
{
T[] arr;
}
void main()
{
A!(int[], double[]) a;
a.arr[0] ~= 5;
a.arr[0] ~= 6;
static assert(!__traits(compiles, a.arr[0] ~= 3.5));
a.arr[1] ~= 19.8;
assert(a.arr[0] == [5,6]);
assert(a.arr[1] == [19.8]);
assert(a.arr[1].length == 1);
assert(a.arr[0].length == 2);
B!(int, double) b;
//b.arr[0] ~= 5;
}
While struct A behaves like expected, how to get by with B?
What I want is just to abstract the array property out of
template arguments...
Thanks in advance :)
b.arr refers to an `(AliasSeq!(int, double))[]`, so with
`b.arr[0] ~= 5;` you are trying to append a integer to an array
of pairs of ints and doubles, which you can't do.
b.arr[0] ~= ElementType!(typeof(b.arr))(5,42.0);
should work (I hope, not tested) but you cannot append only the
int.
If you are trying to abstract the array for struct of array vs.
array of struct the take a look at
https://maikklein.github.io/post/soa-d/
