Re: Template substitution for function parameters

[user1234 via Digitalmars-d-learn]

On Friday, 1 September 2017 at 10:15:09 UTC, Nicholas Wilson 
wrote:
So I have the following types
...
i.e. it substitutes the template DevicePointer for the template 
Buffer in Parameters!foo,
The templates can be assumed to not be nested templates, i.e. 
DevicePointer!(DevicePointer!(float)) will never occur neither 
will Buffer!(Buffer!(float) or any cross templates)

Wow, this Question triggers an immediate headache...What about 
this ?

import std.traits: Parameters;
alias HostArgsOf(alias A) = AliasSeq!(Parameters!A[0], 
Parameters!A[1], Parameters!A[2]);