You can avoid cast:
void foo(T)(T bar){...}
byte bar = 9;
foo!byte(bar + byte(1));
or
byte bar = 9;
byte num = 1;
foo!byte(bar + num);
On Tue, Oct 10, 2017 at 9:55 PM, Chirs Forest via Digitalmars-d-learn <
digitalmars-d-learn@puremagic.com> wrote:
> I keep having to make casts like the following and it's really rubbing me
> the wrong way:
>
> void foo(T)(T bar){...}
>
> byte bar = 9;
>
> foo!byte(bar + 1); //Error: function foo!byte.foo (byte bar) is not
> callable using argument types (int)
> foo!byte(cast(byte)(bar + 1));
>
> It wouldn't be so bad if I didn't have to use the word cast before each
> cast, bust since I have to specify both the word cast and the cast type and
> then wrap both the cast type and the value in brackets... it just explodes
> my code into multiple lines of unreadable mess.
>
>
> void foo(T)(T bar, T bar2, T bar3){...}
>
> byte foobar = 12;
>
> foo!byte(foobar + 1, foobar + 22, foobar + 333);
> vs.
> foo!byte(cast(byte)(foobar + 1), cast(byte)(foobar + 22),
> cast(byte)(foobar + 333));
>
> Why?
>
