On Thursday, 30 November 2017 at 00:40:51 UTC, David Colson wrote:
Hello all!
I'm getting settled into D and I came into a problem. A code
sample shows it best:
class SomeType
{
string text;
this(string input) {text = input;}
}
void main()
{
SomeType foo = new SomeType("Hello");
SomeType bar = foo;
foo = new SomeType("World");
writeln(bar.text); // Prints hello
// I'd like it to print World
}
In the C++ world I could do this using pointers and changing
the data underneath a given pointer, but I can't use pointers
in D, so I'm not sure how I can get this behaviour?
I'd be open to other ways of achieving the same affect in D,
using more D like methods.
You are dealing with a reference type. Reference types can be
though of as a value type of an address. The new operator can be
though of as giving the variable a new address. This means the
foo and bar variables are not bound to the same value because
their referencing different address. You need a struct. Which
isn't a reference.
