Re: free func "front" is not picked up as a candidate when doing range.front(...)

[Paul Backus via Digitalmars-d-learn]

On Wednesday, 7 February 2018 at 19:25:01 UTC, aliak wrote:
    import std.range: iota;
    0.iota.front(100).writeln;
// Error: inout method std.range.iota!(int, 
int).iota.Result.front is not callable using a mutable object

    import std.algorithm: filter;
    auto arr = [0, 1];
    arr.filter!"true".front(99).writeln;
// Error: function 
std.algorithm.iteration.FilterResult!(unaryFun, 
int[]).FilterResult.front () is not callable using argument 
types (int)


You can only call a function with UFCS syntax if the object 
you're calling it with does not have a member with the same name 
as the function. Both iota's `Result` type and `FilterResult` 
have properties named "front", so you can't call your front 
function on them using UFCS syntax.