Re: Assigning a method name to a variable and then calling it with an object

[aliak via Digitalmars-d-learn]

On Thursday, 24 May 2018 at 23:08:29 UTC, Basile B. wrote:

On Thursday, 24 May 2018 at 23:03:21 UTC, aliak wrote:

Hi,

I was essentially trying to do this:

struct S {
  void f() {}
}

auto f = S.f; // f becomes void function(S) ??
S s;
f(s);

Is something like that possible?

Cheers,
- Ali

Sure:

```
import std.stdio;

void main(string[] args)
{

    struct S {
      void f() {"yeah possible".writeln;}
    }

    void delegate() f;
    f.funcptr = &S.f;
    S s;
    f.ptr = &s;
    s.f();
}
```

It's just that you have to learn the ABI of D delegates.

There are two members: .funcptr (function) and .ptr (context, i.e the "this").

ahh, gracias!