On Wednesday, June 13, 2018 07:35:25 RazvanN via Digitalmars-d-learn wrote:
> Hello,
>
> I'm having a hard time understanding whether this inconsistency
> is a bug or intended behavior:
>
> immutable class Foo {}
> immutable struct Bar {}
>
> void main()
> {
> import std.stdio : writeln;
> Foo a;
> Bar b;
>
> writeln("typeof(a): ", typeof(a).stringof);
> writeln("typeof(b): ", typeof(b).stringof);
> }
>
> prints:
>
> typeof(Foo): Foo
> typeof(Bar): immutable(Bar)
>
>
> It seems like the class storage class is not taken into account
> which leads to some awkward situations like:
>
> immutable class Foo
> {
> this() {}
> }
>
> void main()
> {
> Foo a = new Foo(); // error: immutable method `this` is not
> callable using a
> // mutable object
> }
>
> To make it work I have to add immutable to both sides of the
> expression : immutable Foo a = new immutable Foo(); this is a
> wonder of redundancy. I already declared the class as immutable
> so it shouldn't be possible to have mutable instances of it (and
> it isn't), however I am forced to write the immutable twice even
> though it is pretty obvious that the class cannot be mutated.
Honestly, from what I understand of how this works, what I find weird is the
struct case. immutable on classes does _not_ make the class itself
immutable. It just makes all of its members immutable - hence the error
about trying to allocate new Foo instead of new immutable Foo. So, that is
exactly what I would expect. And honestly, being able to write Foo and have
it imply immutable Foo would get _really_ confusing when reading and
debugging code.
What's bizarre is that marking the struct with immutable would affect
anything other than its members.
Bar b;
should not claim that typeof(b) is immutable(Bar). b was not marked as
immutable. It was listed as Bar, not immutable Bar. So, b shouldn't be
immutable.
- Jonathan M Davis
