On Friday, 14 September 2018 at 19:44:37 UTC, berni wrote:
a) I've got an int[] which contains only 0 und 1. And I want to
end with a string, containing 0 and 1. So [1,1,0,1,0,1] should
become "110101". Of course I can do this with a loop and ~. But
I think it should be doable with functional style, which is
something I would like to understand better. Can anyone help me
here? (I think a.map!(a=>to!char(a+'0')) does the trick, but is
this good style or is there a better way?)
b) After having this I'd like to split this resulting string
into chunks of a fixed length, e.g. length 4, so "110101" from
above should become ["1101","01"]. Again, is it possible to do
that with functional style? Probably chunks from std.range
might help here, but I don't get it to work.
All in all, can you fill in the magic functional chain below?
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
auto result = magic functional chain here :-)
assert(result==["1011","1010","1111","0"]);
What you want is std.range.chunks
auto a = [1,0,1,1,1,0,1,0,1,1,1,1,0];
a.map!(to!string)
.join("")
.chunks(4)
.map!(to!string) //don´t know why the chunks are not already
strings at this point ;/
.writeln;
