On Thursday, 8 November 2018 at 14:38:37 UTC, Paul Backus wrote:
To pass these ranges around using the `InputRange` interface,
use `inputRangeObject` to wrap them:
InputRange!ubyte r3 = inputRangeObject(r1);
InputRange!(immutable(ubyte)) r4 = inputRangeObject(r2);
I did a bit more digging, and it seems to work for strings but
not for files: The program
import std.algorithm.iteration;
import std.format;
import std.range;
import std.stdio;
import std.string;
void somefn(InputRange!(immutable(ubyte)) r) {
writeln(format!"%s"(r));
}
void main()
{
auto a = "Hello, world!";
auto b = inputRangeObject(a.representation);
somefn(b);
auto c = stdin.byChunk(1024).joiner;
auto d = inputRangeObject(c);
//somefn(d);
}
compiles as given above, but if the somefn(d) line is
uncommented, I get an error:
function onlineapp.somefn(InputRange!(immutable(ubyte)) r) is not
callable using argument types (InputRangeObject!(Result))
onlineapp.d(18): cannot pass argument d of type
std.range.interfaces.InputRangeObject!(Result) to parameter
InputRange!(immutable(ubyte)) r
Do I need to do an explicit cast? If so, can someone tell me the
precise incantation? How come it doesn't figure out that the
underlying range is a ubyte range, or is it to do with
immutability, or something else altogether?
