On Tuesday, 18 December 2018 at 13:53:01 UTC, Stefan Koch wrote:
Why would you need to know?
Well, first out of curiosity. But there are also other reasons:
I've got a large immutable array. Without CTFE I'd use some php
script and add it as a large literal. With CTFE I don't need that
php script nor do I need to put that large literal in the source
code. But I need to know, that indeed the array is calculated by
the compiler, else the solution with the php script would result
in faster code.
if(__ctfe) assert(0, "Yep, CTFE used");
That seems to work, but unfortunately, my script seems not to be
evaluated at compile time... Here is a small example, similar to
my code, where CTFE is not used:
import std.stdio;
class A
{
static immutable int[4] clue;
static this()
{
if(__ctfe) assert(0, "Yep, CTFE used");
foreach (i;0..4) clue[i] = i;
}
}
void main()
{
auto tmp = new A();
writeln(tmp.clue[2]);
}
Can you help me, finding the problem here?
