On Wednesday, 13 March 2019 at 13:03:27 UTC, tchaloupka wrote:
Is this expected?:
You never called the constructor, which means it was lazy
initialized... but that was done inside one of the functions,
which received the Appender by value.
So when it set its internal pointer, it was inside a function and
never got seen outside. Similar to if you do
char* a;
void foo(char* a) {
a = new char[](10);
}
foo(a);
If you were to put something before the other calls, it would
work. Or call the constructor (which the little-a appender
function does).
I'm kinda of the opinion this should be a compile error; that it
should force you to call the constructor, so that could be a
minor bug, but it isn't unexpected per se since regular pointers
and arrays work the same way.
