Re: Returning reference: why this works?

[Denis Feklushkin via Digitalmars-d-learn]

On Wednesday, 13 March 2019 at 21:04:01 UTC, Johan Engelen wrote:

On Wednesday, 13 March 2019 at 20:57:13 UTC, Denis Feklushkin wrote:

import std.stdio;

struct S { int x; }

ref S func1(ref S i) // i is reference
{
    return i;
}

ref S func2(S i) // i is not reference
{

return func1(i); // Works! Possibility to return reference to local object i?

Indeed, you're invoking UB here. With compiler flag `-dip25` that code no longer compiles.

-Johan

Oh, very unexpected! Thank you very much!