Re: Can't add a const ubyte to a dynamic array of ubyte?

[a11e99z via Digitalmars-d-learn]

On Tuesday, 20 August 2019 at 09:27:36 UTC, ads wrote:

import std.stdio;

ubyte[] extend(in uint[] arr)
{
        ubyte[] result;
        foreach (n; arr)
        {
                if (n < 10)
                        result ~= n;
                else
                {
                        import std.conv : to;
                        foreach (digit; n.to!string)
                                result ~= digit.to!ubyte;
                }
        }
        return result;
}

unittest
{
        import std.algorithm : equal;
        assert(extend([1, 25, 70, 0]).equal([1, 2, 5, 7, 0, 0]));
}

How can I get around this? I want to ensure that the array is not mutated in the function in the signature too.

what u using here?

result ~= digit.to!ubyte;

why not to do same in line?

result ~= n;

2) digit is '0'+(0..9) so u need subtract '0' ('0' is \x30)