On Tuesday, 27 August 2019 at 20:35:16 UTC, bachmeier wrote:
On Tuesday, 27 August 2019 at 20:14:21 UTC, Machine Code wrote:
It isn't really hard:
It really is hard. foo.byPair.array.sort!((a, b) => a.key <
b.key).map!(a => a.value); is a lot to digest for someone
learning the language. There's a big difference between not
being hard for someone that understands what each piece does
and not being hard for someone new to D. At a minimum, it would
help to write it
foo.byPair
.array
.sort!((a, b) => a.key < b.key)
.map!(a => a.value);
I wrote expression with string lambdas for one purpose:
when u see very simple beauty thing that is working and u totally
doesn't understand how exactly, ur curiosity should do the rest
of the work. it's worth sorting out.
if man wanted just do his job, he got this too.
