On 2019-11-15 17:23:38 +0000, Steven Schveighoffer said:

On 11/15/19 12:05 PM, Robert M. Münch wrote:
JSONValue j = parseJSON(json_string).object;

 writeln(j);                             // works
 writeln(j["a"]);                     // works
 writeln(j["a"].object["b"]);     // bombs

Maybe your "a" value is not an object?

Thanks, it's an array... why ever... I need to use:

        writeln(j["a"][0]["b"]);

Wasn't that obvious, because it's a big JSON structure.

--
Robert M. Münch
http://www.saphirion.com
smarter | better | faster

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