On 2019-11-15 17:23:38 +0000, Steven Schveighoffer said:
On 11/15/19 12:05 PM, Robert M. Münch wrote:JSONValue j = parseJSON(json_string).object; writeln(j); // works writeln(j["a"]); // works writeln(j["a"].object["b"]); // bombsMaybe your "a" value is not an object?
Thanks, it's an array... why ever... I need to use: writeln(j["a"][0]["b"]); Wasn't that obvious, because it's a big JSON structure. -- Robert M. Münch http://www.saphirion.com smarter | better | faster