On Tue, 03 Feb 2009 22:43:06 +0300, Steven Schveighoffer <[email protected]> 
wrote:

"Denis Koroskin" wrote
On Tue, 03 Feb 2009 21:25:21 +0300, Sean Kelly <[email protected]>
wrote:

Andrei Alexandrescu wrote:
Ary Borenszweig wrote:
Andrei Alexandrescu escribió:
I've updated my code and documentation to include series (as in math)
in the form of infinite ranges. Also series in closed form (given n
can compute the nth value without iterating) are supported as
random-access ranges.

Also Stride is provided. The Matrix container (speaking of scientific
computing with D!) will support various representational choices,
most importantly the ones endorsed by high-performance libraries. For
Matrix, Stride is an important component as I'm sure anyone who's
ever written a matrix knows.

http://ssli.ee.washington.edu/~aalexand/d/web/phobos/std_range.html
http://ssli.ee.washington.edu/~aalexand/d/web/phobos/std_algorithm.html

Back to series. Finally my dream has come true: I can define a decent Fibonacci series clearly and efficiently in one line of code. No more
idiotic recursive function that takes exponential time to finish!

auto fib = series!("a[n-1] + a[n]")(1, 1);
// write 10 Fibonacci numbers
foreach (e; take(10, fib)) writeln(e);

That is *SO* awesome!!
 Thanks! Constant-space factorial is just a line away:
 auto fact = series!("a[n] * (n + 1)")(1);
foreach (e; take(10, fact)) writeln(e);

Awesome :-)  I think that proves the efficacy of the approach all by
itself.


Sean

I wonder how efficent it is? Does it store last few sequence elements or
re-compute then again and again?
I wouldn't use it in the latter case.

Factorial series is defined in terms of the last term, so you only need to
remember the last term.  i.e. 5! = 4! * 5.

So constant space, constant time per iteration.


Of course, but does it *really* discard old values? That's what I doubt.

Ok, Factorial/Fibonacci is easy. How would you implement, say, the following 
sequence:
a[n] = a[0] + a[n / 8]; // ?

Now it is log(n) to compute from scratch but you should store O(n) elements to 
make it constant time.

I mean, the algorithm ought to have very good heuristics.
And sometimes it is better to re-compute elements instead of caching them.

One thing I was confused about, you are defining in the function how to
calculate a[n+1]?  I find it more intuitive to define what a[n] is.  For
example,

auto fib = series!("a[n - 2] + a[n - 1]")(1, 1); // reads a[n] = a[n-2] +
a[n-1]

It's even less confusing in the factorial example (IMO):

auto fact = series!("a[n - 1] * n")(1);

Of course, I don't know how the template-fu works, so I'm not sure if it's
possible ;)

-Steve



I agree.

Reply via email to