invariant()

[Michel Fortin]

In D1 you had to write:

        invariant
        {
                ...
        }
while in D2, to disabiguate with invariant being overloaded with 
immutability you had to write:

        invariant()
        {
                ...
        }

Now that the use of the invariant keyword in D2 has returned to its 
single original meaning of class invariant, is there still a reason for 
it to require an empty parenthesis? Should I fill a bug?

--
Michel Fortin
michel.for...@michelf.com
http://michelf.com/