On 2013-01-06 15:25, Philippe Sigaud wrote:
That would mean two mixins, one internal and one external. Plus, that
means every function where I want to propagate UDA has to be crafted
exactly for this need.
This is a drag. It seems natural to me that
int foo(int i) { return i;}
should forward i attributes. But maybe I need a shift my way to think
about attributes. They are attached to declarations, not values...
Exactly.
That's too bad, because declaring UDA is simple, and receiving them with
arguments is easy also. There is a fundamental imbalance in having
having propagating attributes through functions so difficult.
Yeah, if you want to work with UDA's you need to work with symbols, not
values or types. If you want to pass a symbol, including its UDA, you
need to pass it as an alias:
void foo (alias symbol) ()
{
// access UDA of symbol
}
@(3) int a;
foo!(a);
--
/Jacob Carlborg
