Tim Matthews Wrote: > On Fri, 15 May 2009 22:29:07 +1200, Robert Fraser > <[email protected]> wrote: > > > Vladimir A. Reznichenko wrote: > >> I have a function: > >> void test (inout uint a) > >> { > >> asm > >> { > >> mov a, 0x25; > >> } > >> } > >> The trouble is that the function's call doesn't change the a variable. > >> Any ideas? > > > > Inout variables are pointers. > > > Why is it 'inout' and not 'ref' ?
Aren't they the same?
